Travelling salesman problem 5 cities

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**salesman**starting**city**is A, then a TSP tour in the graph is-A → B → D → C → A . Cost of the tour = 10 + 25 + 30 + 15 = 80 units . In this article, we will discuss how to solve**travelling salesman problem**using branch and bound approach with example. PRACTICE**PROBLEM**BASED ON**TRAVELLING SALESMAN PROBLEM**USING BRANCH AND BOUND ... - *
**Travelling salesman problem**asks: * Given a list of**cities**and the distances between each pair of**cities**, what is * the shortest possible route that visits each**city**exactly once and returns to * the origin**city**? * TSP can be modeled as an undirected weighted graph, such that**cities**are the - The ‘
**Travelling salesman problem**’ is very similar to the assignment**problem**except that in the former, there are additional restrictions that a**salesman**starts from his**city**, visits each**city**once and returns to his home**city**, so that the total distance (cost or time) is minimum. Procedure: Step 1: Solve the**problem**as an assignment**problem**. - The
**problem**is commonly referred to as the "**Traveling Salesman Problem**." Finding an optimal route becomes more challenging as the number of**cities**involved increases. For instance, to solve for the most economical way for a**traveling salesman**to tour five**cities**the researcher can take a straightforward method, having the computer calculate the - There is no polynomial-time know solution for this
**problem**. The following are different solutions for the**traveling salesman problem**. Naive Solution: 1) Consider**city**1 as the starting and ending point. 2) Generate all (n-1)! Permutations of**cities**. 3) Calculate the cost of every permutation and keep track of the minimum cost permutation.